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CBSE 14 min read21 October 2026

Class 12 p-Block Elements Complete Guide 2027 — Group 15-18 Reactions, Oxoacids, Interhalogen Compounds

Master p-Block Elements for CBSE Class 12 Chemistry 2027. Group 15 nitrogen family, Group 16 oxygen family, Group 17 halogens, Group 18 noble gases — anomalous behaviour, key reactions, oxoacids, interhalogen compounds for 8 marks.

In short: p-Block Elements (Chapters 7-8) is the highest-weightage inorganic chapter in CBSE Class 12 Chemistry, carrying a combined 8 marks out of 70. It spans Group 15 (nitrogen family), Group 16 (oxygen family), Group 17 (halogens), and Group 18 (noble gases). The chapter is vast but pattern-driven — learn the anomalous behaviour of the first element in each group, memorise the key reactions and structures of oxoacids, and know the preparation and properties of important compounds (NH₃, HNO₃, H₂SO₄, and interhalogen compounds). Boards love the comparison tables and equation-writing questions. Invest time here and you secure 8 marks from pure memory work.

p-Block Elements is split across Chapters 7 and 8 in the NCERT textbook, covering Groups 15 through 18. Together, they form the largest inorganic chemistry block on the CBSE Class 12 paper. Unlike Physical Chemistry, this chapter does not require derivations or complex calculations — it rewards structured memorisation and the ability to write balanced equations quickly.

For the full marks breakdown across all chapters, see the Class 12 Chemistry chapter-wise weightage. For all reactions in one place, check the Class 12 Chemistry formulas and reactions list.

Marks Distribution

TopicType of QuestionsExpected Marks
Group 15: Nitrogen family (NH₃, HNO₃, allotropy, oxoacids)2-3 mark theory/equations2-3
Group 16: Oxygen family (O₃, H₂SO₄, oxoacids, structures)2-3 mark theory/equations2-3
Group 17: Halogens (HX acids, interhalogen compounds, oxoacids)2-3 mark theory/equations2-3
Group 18: Noble gases (compounds of Xe, structures)1-mark MCQ/short answer0-1
Total8

Group 15 — The Nitrogen Family (N, P, As, Sb, Bi)

General Trends

PropertyTrend down the group
Atomic radiusIncreases
Ionisation enthalpyDecreases (but higher than Group 14 and 16 due to stable half-filled p³ configuration)
ElectronegativityDecreases
Metallic characterIncreases (N, P = non-metals; As = metalloid; Sb, Bi = metals)
Oxidation states-3, +3, +5; stability of +5 state decreases down the group (inert pair effect)

Anomalous Behaviour of Nitrogen

Nitrogen differs from the rest of Group 15 because of:

  1. Small size and high electronegativity
  2. No d-orbitals — cannot expand its covalence beyond 4 (unlike P which forms PCl₅)
  3. Strong tendency to form pπ-pπ multiple bonds — N₂ has a triple bond (N≡N), making it very stable
  4. Can form hydrogen bonds — NH₃ has higher boiling point than PH₃

Memory trick: "Nitrogen is Small, No d-orbitals, Strong triple bond, hydrogen bonding" → "S-N-S-H".

Important Compounds of Nitrogen

Ammonia (NH₃)

  • Lab preparation: NH₄Cl + Ca(OH)₂ → CaCl₂ + 2H₂O + 2NH₃
  • Haber's process: N₂ + 3H₂ ⇌ 2NH₃ (conditions: 200 atm, 700 K, Fe catalyst with Mo promoter)
  • Properties: Basic gas, turns red litmus blue, forms white fumes with HCl (NH₄Cl)
  • Structure: Trigonal pyramidal, sp³ hybridised, bond angle 107.8°

Nitric Acid (HNO₃)

  • Ostwald process: 4NH₃ + 5O₂ → 4NO + 6H₂O (Pt/Rh catalyst, 500 K)
  • Then: 2NO + O₂ → 2NO₂ → NO₂ + H₂O → HNO₃
  • Strong oxidising agent: Cu + 8HNO₃(dilute) → 3Cu(NO₃)₂ + 2NO + 4H₂O
  • Brown ring test for NO₃⁻: FeSO₄ + NO₃⁻ + H₂SO₄ → [Fe(H₂O)₅NO]²⁺ (brown ring)

Oxoacids of Nitrogen

OxoacidFormulaN Oxidation State
Hyponitrous acidH₂N₂O₂+1
Nitrous acidHNO₂+3
Nitric acidHNO₃+5

Allotropes of Phosphorus

AllotropeStructureProperties
White PP₄ tetrahedralWaxy, poisonous, glows in dark (chemiluminescence), stored in water
Red PPolymeric chainsNon-toxic, does not glow, stable in air
Black PLayered structureMost stable, resembles graphite

Group 16 — The Oxygen Family (O, S, Se, Te, Po)

General Trends

PropertyTrend
Oxidation states-2, +2, +4, +6 (oxygen shows only -2 and rarely -1 in peroxides)
Stability of -2 stateDecreases down the group
Stability of +6 stateDecreases down the group (inert pair effect)
Bond dissociation enthalpy of H₂XDecreases: H₂O > H₂S > H₂Se > H₂Te
Acidic strength of H₂XIncreases: H₂O < H₂S < H₂Se < H₂Te

Anomalous Behaviour of Oxygen

  1. Small size and high electronegativity (second only to fluorine)
  2. No d-orbitals — maximum covalence is 2, unlike S which can be 6 (SF₆)
  3. Forms strong pπ-pπ bonds — O=O double bond is strong, O₂ exists as diatomic molecule
  4. Oxygen shows -2 oxidation state only (no positive states in normal compounds)

Ozone (O₃)

  • Preparation: 3O₂ → 2O₃ (UV radiation or silent electric discharge)
  • Structure: Angular/bent, bond angle 116.8°, resonance hybrid
  • Powerful oxidising agent: PbS + 4O₃ → PbSO₄ + 4O₂
  • Test for ozone: Turns moist KI paper brown (KI + O₃ → KOH + I₂ + O₂)

Sulphuric Acid (H₂SO₄)

Contact process:

  1. S + O₂ → SO₂
  2. 2SO₂ + O₂ ⇌ 2SO₃ (V₂O₅ catalyst, 720 K, 2 atm)
  3. SO₃ + H₂SO₄ → H₂S₂O₇ (oleum)
  4. H₂S₂O₇ + H₂O → 2H₂SO₄

Properties:

  • Strong dibasic acid, dehydrating agent, oxidising agent
  • Concentrated H₂SO₄ chars sugar (removes water): C₁₂H₂₂O₁₁ → 12C + 11H₂O

Oxoacids of Sulphur

OxoacidFormulaS Oxidation State
Sulphurous acidH₂SO₃+4
Sulphuric acidH₂SO₄+6
Thiosulphuric acidH₂S₂O₃+2
Peroxodisulphuric acidH₂S₂O₈+7

Board exam tip: Drawing structures of oxoacids is a common 2-mark question. Remember that S uses d-orbitals to expand its valence shell. Each S-O single bond has one lone pair on O; each S=O double bond does not.

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Group 17 — The Halogens (F, Cl, Br, I, At)

General Trends

PropertyTrend
ElectronegativityF > Cl > Br > I (F is most electronegative element)
Electron gain enthalpyCl > F > Br > I (F is anomalous — small size, high e⁻-e⁻ repulsion)
Oxidation statesF: -1 only; Cl, Br, I: -1, +1, +3, +5, +7
Bond dissociation enthalpy of X₂Cl₂ > Br₂ > F₂ > I₂ (F₂ is anomalous — lone pair repulsion)
Acidic strength of HXHI > HBr > HCl > HF (HF is weak acid due to strong H-F bond)
Reducing power of HXHI > HBr > HCl > HF

Anomalous Behaviour of Fluorine

  1. Smallest size, highest electronegativity of all elements
  2. No d-orbitals — only shows -1 oxidation state (no positive states)
  3. F₂ has lower bond dissociation enthalpy than Cl₂ — lone pairs on F atoms are very close together, causing repulsion
  4. HF is a weak acid — H-F bond is extremely strong (568 kJ/mol)
  5. F forms hydrogen bonds — HF has abnormally high boiling point

Memory trick — "Fluorine is FENO": First element, Electronegative, No d-orbitals, Only -1 state.

Interhalogen Compounds

Formed between two different halogens where the larger halogen is the central atom.

TypeFormula ExamplesStructureHybridisation
XX'ClF, BrF, ICl, IBrLinearsp
XX'₃ClF₃, BrF₃, ICl₃T-shapedsp³d
XX'₅BrF₅, IF₅Square pyramidalsp³d²
XX'₇IF₇Pentagonal bipyramidalsp³d³

Properties: More reactive than parent halogens (bond X-X' is weaker than X-X). Hydrolysed by water to give hydrohalic acid and hypohalous acid.

Oxoacids of Chlorine

OxoacidFormulaCl Oxidation StateAcidic Strength
Hypochlorous acidHOCl+1Weakest
Chlorous acidHClO₂+3↓
Chloric acidHClO₃+5↓
Perchloric acidHClO₄+7Strongest

Trend: As the number of oxygen atoms increases, the acidic strength increases (more O atoms stabilise the conjugate base through delocalisation).

Group 18 — The Noble Gases (He, Ne, Ar, Kr, Xe, Rn)

Why Noble Gases Are Inert

  • Fully filled valence shell (ns²np⁶, except He: 1s²)
  • Very high ionisation enthalpy
  • Large positive electron gain enthalpy

Compounds of Xenon

Noble gases were once thought to be completely inert. In 1962, Bartlett prepared XePtF₆, and since then several Xe compounds have been made.

CompoundHybridisationStructureGeometry
XeF₂sp³dLinearLinear (3 lone pairs)
XeF₄sp³d²Square planarSquare planar (2 lone pairs)
XeF₆sp³d³Distorted octahedralDistorted octahedral (1 lone pair)
XeO₃sp³PyramidalPyramidal
XeOF₂sp³dT-shapedT-shaped

Board exam tip: Drawing the structures of XeF₂, XeF₄, and XeF₆ showing lone pairs is a favourite 2-mark question. Remember VSEPR — count total electron pairs around Xe to get the hybridisation.

Board Exam Question Types

  1. Write balanced equations — for the preparation of NH₃ (Haber's process), HNO₃ (Ostwald process), H₂SO₄ (Contact process). (2-3 marks) — Very high frequency
  2. Explain the anomalous behaviour of nitrogen/oxygen/fluorine giving any 3 reasons. (3 marks)
  3. Draw the structures of oxoacids of sulphur or nitrogen or chlorine. (2 marks)
  4. Give reasons — Why does N₂ have a higher bond dissociation enthalpy than O₂? Why is HF a weak acid despite being highly polar? Why is electron gain enthalpy of Cl more negative than F? (2 marks each)
  5. Interhalogen compounds — types, examples, one structure, properties. (2-3 marks)
  6. Xenon fluoride structures — draw XeF₂ and XeF₄ showing hybridisation and lone pairs. (2 marks)
  7. Compare/contrast — oxidising power of halogens, acidic strength of HX acids, reducing power of hydrides. (2-3 marks)

Common Mistakes Students Make

  1. Writing wrong equations for the Ostwald process. Students often jump directly to HNO₃ formation without showing the intermediate steps (NH₃ → NO → NO₂ → HNO₃). The board paper expects all three steps. Write them separately with conditions (catalyst, temperature).

  2. Confusing electron gain enthalpy order of halogens. The order is Cl > F > Br > I, not F > Cl > Br > I. Fluorine's small size causes intense electron-electron repulsion in the 2p subshell, making its electron gain enthalpy less negative than chlorine's. This is asked almost every year.

  3. Forgetting the anomalous behaviour reasons. Students know that nitrogen is anomalous but cannot articulate why. The three key reasons are always: (a) small size, (b) no d-orbitals, (c) strong pπ-pπ bonding. Memorise these for all three first elements (N, O, F).

  4. Drawing wrong structures for XeF₂ and XeF₄. XeF₂ is linear (not bent) because the three lone pairs occupy equatorial positions in a trigonal bipyramidal arrangement. XeF₄ is square planar (not tetrahedral) because the two lone pairs sit opposite each other to minimise repulsion.

  5. Mixing up the acidic strength trend of HX and oxoacids. For hydrohalic acids: HI > HBr > HCl > HF (bond strength decreases down the group). For oxoacids of a given halogen: HClO₄ > HClO₃ > HClO₂ > HOCl (more oxygen atoms = stronger acid). These trends run in opposite logical directions.

  6. Not specifying conditions in chemical equations. Board examiners deduct marks if you write N₂ + 3H₂ → 2NH₃ without mentioning "Fe catalyst, Mo promoter, 200 atm, 700 K." Always include temperature, pressure, and catalyst where applicable.

4-Week Practice Plan

Week 1: Group 15 — Nitrogen Family

  • Read NCERT Chapter 7, Sections 7.1-7.7 carefully
  • Make a comparison table of all Group 15 elements (size, EN, oxidation states, hydrides)
  • Memorise the 3 anomalous behaviour reasons for nitrogen
  • Write out the Haber's process and Ostwald process equations with conditions 5 times each
  • Draw structures of all oxoacids of nitrogen

Week 2: Group 16 — Oxygen Family

  • Read NCERT Chapter 7, Sections 7.8-7.14
  • Make a comparison table for Group 16 (same format as Week 1)
  • Memorise the Contact process (all 4 steps with conditions)
  • Draw structures of oxoacids of sulphur
  • Practise 5 "give reasons" questions on oxygen anomaly and ozone properties

Week 3: Group 17 & 18 — Halogens and Noble Gases

  • Read NCERT Chapter 7, Sections 7.15-7.26
  • Make comparison tables for halogens (EN, electron gain enthalpy, acidic strength of HX, oxidising power)
  • Memorise all 4 types of interhalogen compounds with structures and hybridisation
  • Draw structures of XeF₂, XeF₄, XeF₆, and XeO₃ with lone pairs
  • Write the oxoacids of chlorine in order of acidic strength

Week 4: Revision & Board-Pattern Practice

  • Solve 4 previous year board papers (p-block questions only)
  • Take a 45-minute chapter test covering all 4 groups
  • Revise all chemical equations (aim to write each from memory)
  • Focus on "give reasons" and "draw structure" questions — they carry the most marks
  • Review the quick revision card below

Quick Revision Card

TopicKey Fact to Remember
N anomalySmall size, no d-orbitals, pπ-pπ bonds
Haber's processN₂ + 3H₂ ⇌ 2NH₃ (Fe/Mo, 200 atm, 700 K)
Ostwald processNH₃ → NO → NO₂ → HNO₃ (Pt/Rh, 500 K)
Contact processSO₂ → SO₃ → oleum → H₂SO₄ (V₂O₅, 720 K)
Electron gain enthalpyCl > F > Br > I (F is anomalous)
HX acid strengthHI > HBr > HCl > HF
Oxoacid strength (Cl)HClO₄ > HClO₃ > HClO₂ > HOCl
Interhalogen typesXX', XX'₃, XX'₅, XX'₇
XeF₂sp³d, linear, 3 lone pairs
XeF₄sp³d², square planar, 2 lone pairs
Allotropes of PWhite (P₄), Red (polymeric), Black (layered)
F anomalySmallest, most EN, no d-orbitals, only -1 state

One-liner mnemonics:

  • "S-N-S-H" for N anomaly — Small, No d-orbitals, Strong triple bond, H-bonding
  • "FENO" for F anomaly — First element, Electronegative, No d-orbitals, Only -1
  • "HOCl → HClO₄ = Weak → Strong" — more oxygen = stronger acid
  • "Cl wins over F in EGE" — Cl has more negative electron gain enthalpy than F

Frequently Asked Questions

How many marks do the p-Block Elements carry in CBSE 2027?

The p-Block Elements carry 8 marks out of 70, making it the highest-scoring inorganic chapter in CBSE Class 12 Chemistry. It is split across two NCERT chapters (Chapter 7 and 8), but the exam treats them as one unit.

Is this chapter mostly theory or numericals?

It is entirely theory-based. There are no numericals in p-Block Elements. The questions focus on writing equations with conditions, explaining trends, drawing structures, and "give reasons" type answers. This makes it a pure memorisation chapter.

Which group is most important for the board exam?

Group 17 (Halogens) and Group 15 (Nitrogen family) appear most frequently. Questions on anomalous behaviour of the first element, interhalogen compounds, and industrial processes (Haber, Ostwald, Contact) are near-guaranteed.

How do I remember all the reactions in this chapter?

Group the reactions by type: (a) industrial preparations (Haber, Ostwald, Contact), (b) lab preparations (NH₃ from NH₄Cl), (c) chemical properties (oxidising reactions of HNO₃ and H₂SO₄). Write each equation daily for a week — muscle memory works.

Why is this chapter considered the hardest in inorganic chemistry?

Because of its sheer volume. It covers 4 groups, dozens of compounds, and scores of equations. The content itself is not difficult — it is mostly factual. The challenge is memorisation and retention. A structured weekly plan (one group per week) works much better than trying to cram everything at once.

Are structures of oxoacids important for the board exam?

Yes, very important. Drawing the structures of 2-3 oxoacids (of sulphur, nitrogen, or chlorine) is a common 2-mark question. Know which bonds are single (S—OH) and which are double (S=O). Practice drawing them with proper lone pairs.

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