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CBSE 15 min read21 October 2026

Class 12 Coordination Compounds Complete Guide 2027 — IUPAC Naming, Isomerism, VBT, CFT

Master Coordination Compounds for CBSE Class 12 Chemistry 2027. IUPAC naming rules step-by-step, isomerism (geometric, optical, linkage, ionisation), Werner's theory, VBT, CFT for octahedral and tetrahedral complexes — complete guide for 6 marks.

In short: Coordination Compounds (Chapter 5) carries 6 marks in CBSE Class 12 Chemistry 2027 and is one of the most scoring inorganic chapters once you understand the system. It covers Werner's coordination theory, IUPAC naming of complex compounds, types of isomerism (geometric, optical, linkage, ionisation, coordination), Valence Bond Theory (VBT), and Crystal Field Theory (CFT) for octahedral and tetrahedral complexes. Expect 1 naming question, 1 isomerism question, and 1 CFT-based question almost every year. Learn the naming rules as a step-by-step algorithm, memorise the spectrochemical series, and this chapter guarantees you 6 marks.

Coordination Compounds is Chapter 5 in CBSE Class 12 Chemistry and sits at the intersection of inorganic chemistry and bonding theory. It carries 6 marks on the board paper — typically one question on naming (2-3 marks), one on isomerism (2 marks), and one on CFT or VBT (2-3 marks). Unlike p-Block, this chapter rewards understanding over rote learning. Once you grasp the naming algorithm and CFT diagrams, every question becomes solvable.

For the full marks breakdown, see the Class 12 Chemistry chapter-wise weightage. For all formulas and reactions, check the Class 12 Chemistry formulas and reactions list.

Marks Distribution

TopicType of QuestionsExpected Marks
IUPAC naming of coordination compounds2-3 mark naming/writing formulas2-3
Isomerism in coordination compounds2-mark theory/identification2
CFT (crystal field splitting, colour, magnetism)2-3 mark theory/diagram2-3
Werner's theory, VBT basics1-2 mark MCQ/short answer0-1
Total6

Werner's Coordination Theory

Alfred Werner (1913 Nobel Prize) proposed that metals have two types of valency:

  1. Primary valency (ionisable): Corresponds to the oxidation state of the metal. Satisfied by negative ions. Non-directional.
  2. Secondary valency (non-ionisable): Corresponds to the coordination number. Satisfied by ligands. Directional — determines the geometry.

Example — [Co(NH₃)₆]Cl₃:

  • Primary valency = 3 (three Cl⁻ ions, ionisable)
  • Secondary valency = 6 (six NH₃ ligands, non-ionisable, arranged octahedrally)

Key Terms

TermDefinitionExample
Central metal ionThe metal atom/ion to which ligands are attachedCo³⁺ in [Co(NH₃)₆]³⁺
LigandA molecule or ion that donates a lone pair to the metalNH₃, Cl⁻, CN⁻, H₂O
Coordination numberNumber of ligand donor atoms bonded to the metal6 in [Co(NH₃)₆]³⁺
Coordination sphereThe metal and its ligands enclosed in square brackets[Co(NH₃)₆]³⁺
Counter ionIon outside the coordination sphereCl⁻ in [Co(NH₃)₆]Cl₃

Types of Ligands

TypeDonor AtomsExamples
Monodentate1NH₃, Cl⁻, H₂O, CN⁻, NO₂⁻
Bidentate2en (ethylenediamine), ox²⁻ (oxalate C₂O₄²⁻)
Polydentate3+EDTA⁴⁻ (hexadentate — 6 donor atoms)
Ambidentate1 (but has 2 possible donor atoms)NO₂⁻ (N or O), SCN⁻ (S or N)

Memory trick — "AMP": Ambidentate has Multiple Possible donor atoms (but uses only one at a time).

IUPAC Naming Rules — Step by Step

Follow this algorithm every time and you will never get a naming question wrong.

Step 1: Identify the Cation and Anion

  • Write the cation name first, then the anion name (just like NaCl = sodium chloride)
  • If the complex is the cation: [Co(NH₃)₆]Cl₃ → hexaamminecobalt(III) chloride
  • If the complex is the anion: K₃[Fe(CN)₆] → potassium hexacyanoferrate(III)

Step 2: Name the Ligands (Alphabetical Order)

Ligand typeNaming ruleExamples
Anionic (end in -o)Rename ending: -ide → -o, -ate → -ato, -ite → -itoCl⁻ → chlorido, CN⁻ → cyanido, SO₄²⁻ → sulphato, NO₂⁻ → nitrito/nitro
Neutral (no change)Use the molecule nameNH₃ → ammine, H₂O → aqua, CO → carbonyl, NO → nitrosyl
Special namesMust memoriseNH₃ = ammine (not amine), H₂O = aqua, CO = carbonyl

Step 3: Use Prefixes for Number of Ligands

NumberSimple ligand prefixComplex ligand prefix
2di-bis-
3tri-tris-
4tetra-tetrakis-
5penta-pentakis-
6hexa-hexakis-

Use bis-, tris-, tetrakis- when the ligand name already contains di-, tri-, etc. (e.g., ethylenediamine → bis(ethylenediamine)).

Step 4: Name the Metal

  • If complex is a cation or neutral: use the metal name → cobalt, platinum, copper
  • If complex is an anion: add -ate suffix (use Latin name where applicable) → ferrate (Fe), cuprate (Cu), argentate (Ag), aurate (Au), plumbate (Pb), stannate (Sn)
  • Write the oxidation state in Roman numerals in parentheses: cobalt(III), ferrate(III)

Step 5: Put It Together

Order within the coordination sphere: Ligands in alphabetical order → Metal → (Oxidation state)

Worked examples:

ComplexIUPAC Name
[Co(NH₃)₆]Cl₃Hexaamminecobalt(III) chloride
[CoCl₂(en)₂]ClDichloridobis(ethylenediamine)cobalt(III) chloride
K₃[Fe(CN)₆]Potassium hexacyanidoferrate(III)
[Pt(NH₃)₂Cl₂]Diamminedichloridoplatinum(II)
[Ni(CO)₄]Tetracarbonylnickel(0)
K₂[PdCl₄]Potassium tetrachloridopalladate(II)

Memory trick for naming order: "Ligands Alphabetically, Metal, Oxidation state" → "LAM-O". Anionic ligands end in -o, neutral keep their name (except NH₃ = ammine, H₂O = aqua).

Types of Isomerism

Structural Isomerism

TypeDefinitionExample
Linkage isomerismAmbidentate ligand bonds through different donor atoms[Co(NH₃)₅(NO₂)]²⁺ (nitro, N-bonded) vs [Co(NH₃)₅(ONO)]²⁺ (nitrito, O-bonded)
Ionisation isomerismExchange of an ion between coordination sphere and counter ion[Co(NH₃)₅Br]SO₄ (gives SO₄²⁻ test) vs [Co(NH₃)₅SO₄]Br (gives Br⁻ test)
Coordination isomerismExchange of ligands between cationic and anionic complex[Co(NH₃)₆][Cr(CN)₆] vs [Cr(NH₃)₆][Co(CN)₆]
Solvate/Hydrate isomerismWater inside vs outside coordination sphere[Cr(H₂O)₆]Cl₃ (violet) vs [Cr(H₂O)₅Cl]Cl₂·H₂O (green)

Stereoisomerism

Geometric (cis-trans) isomerism:

  • Occurs in square planar and octahedral complexes
  • Square planar [MA₂B₂]: cis (same-side) and trans (opposite-side)
  • Octahedral [MA₂B₄]: cis (adjacent) and trans (opposite)
  • Example: cis-[Pt(NH₃)₂Cl₂] (cisplatin — anti-cancer drug) vs trans-[Pt(NH₃)₂Cl₂]

Optical isomerism:

  • Non-superimposable mirror images (like left and right hands)
  • Occurs in octahedral complexes with bidentate ligands: [Co(en)₃]³⁺
  • d-form (dextrorotatory) rotates plane-polarized light to the right
  • l-form (laevorotatory) rotates it to the left
  • Racemic mixture: equal mixture of d and l forms (no net rotation)

Board exam tip: The board frequently asks "Does [Pt(NH₃)₂Cl₂] show geometrical isomerism? Draw the isomers." Always draw both cis and trans structures clearly with labels.

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Valence Bond Theory (VBT)

VBT explains bonding in coordination compounds using hybridisation of metal orbitals.

How VBT Works

  1. The central metal ion provides empty hybrid orbitals
  2. Ligands donate lone pairs into these empty orbitals
  3. The hybridisation determines the geometry
Coordination NumberHybridisationGeometryExample
4sp³Tetrahedral[NiCl₄]²⁻
4dsp²Square planar[Ni(CN)₄]²⁻
6sp³d²Octahedral (outer orbital)[CoF₆]³⁻
6d²sp³Octahedral (inner orbital)[Co(NH₃)₆]³⁺

Inner vs Outer orbital complexes:

  • Inner orbital (low spin): d²sp³ — uses (n-1)d orbitals, electrons pair up, fewer unpaired electrons → diamagnetic or weakly paramagnetic
  • Outer orbital (high spin): sp³d² — uses nd orbitals, electrons remain unpaired → strongly paramagnetic

Limitation of VBT: Cannot explain colour of coordination compounds, cannot predict whether a complex will be inner or outer orbital without additional data.

Crystal Field Theory (CFT)

CFT is the more modern and complete theory. It treats the metal-ligand interaction as purely electrostatic (ligand lone pairs repel metal d-electrons).

Octahedral Complexes

In a free metal ion, all five d-orbitals have the same energy (degenerate). In an octahedral field:

  • Two d-orbitals point directly at ligands (dz², dx²-y²) → these experience greater repulsion → higher energy → called eᵍ set
  • Three d-orbitals point between ligands (dxy, dyz, dxz) → less repulsion → lower energy → called t₂ᵍ set

Crystal field splitting energy: Δₒ (or 10 Dq)

The eᵍ orbitals are +0.6Δₒ above the average, and t₂ᵍ orbitals are -0.4Δₒ below.

Filling of electrons depends on Δₒ vs pairing energy (P):

  • If Δₒ > P → electrons pair up in t₂ᵍ first → low spin (strong field)
  • If Δₒ < P → electrons fill all orbitals singly first → high spin (weak field)

Tetrahedral Complexes

  • Splitting pattern is inverted: t₂ set is higher, e set is lower
  • Δₜ ≈ (4/9)Δₒ → splitting is much smaller
  • Tetrahedral complexes are almost always high spin (Δₜ is too small to force pairing)

Spectrochemical Series

Ligands arranged in order of increasing field strength (increasing Δ):

I⁻ < Br⁻ < SCN⁻ < Cl⁻ < S²⁻ < F⁻ < OH⁻ < ox²⁻ < H₂O < NCS⁻ < en < NO₂⁻ < NH₃ < CN⁻ < CO

Weak field (left) → small Δ → high spin Strong field (right) → large Δ → low spin

Memory trick: "I Brought Stamps, Chlorine Says Funny, Oh Her Oxalate Has Not Nailed All Carbon Notes Completely Over" — take the first letter of each word to recall the ligand order.

Colour of Coordination Compounds

When a d-electron absorbs light of energy equal to Δ, it jumps from the lower set to the upper set. The colour we see is the complementary colour of the absorbed light.

Absorbed ColourObserved Colour
VioletYellow-green
BlueOrange
GreenRed
YellowViolet
RedGreen

Why [Ti(H₂O)₆]³⁺ is purple: Ti³⁺ has 1 d-electron. It absorbs green-yellow light (Δₒ energy) and transmits purple.

Why d⁰ and d¹⁰ complexes are colourless: No d-d transition is possible (no electron to excite, or no empty orbital to receive it). Example: [Zn(NH₃)₄]²⁺ (d¹⁰) is colourless.

Solved Examples

Example 1: IUPAC Naming

Q: Write the IUPAC name of [CrCl₂(en)₂]Cl.

Solution:

  • Complex is the cation: [CrCl₂(en)₂]⁺, counter ion: Cl⁻
  • Ligands: Cl⁻ → chlorido (×2 = dichlorido), en → ethylenediamine (×2 = bis(ethylenediamine))
  • Alphabetical order: chlorido before ethylenediamine
  • Metal: Cr, oxidation state: let x + (-2) + 0 = +1 → x = +3 → chromium(III)
  • Name: Dichloridobis(ethylenediamine)chromium(III) chloride

Example 2: CFT — Magnetic Nature

Q: Predict the number of unpaired electrons and magnetic nature of [Fe(CN)₆]⁴⁻.

Solution:

  • Fe²⁺ has d⁶ configuration
  • CN⁻ is a strong field ligand → Δₒ is large → low spin complex
  • In low spin octahedral d⁶: all 6 electrons fill t₂ᵍ (t₂ᵍ⁶ eᵍ⁰)
  • Unpaired electrons = 0
  • Diamagnetic

Example 3: Isomerism

Q: How many geometrical isomers are possible for [Co(NH₃)₃Cl₃]? Draw them.

Solution:

  • Octahedral complex of type [MA₃B₃]
  • Two geometrical isomers:
    1. fac (facial): Three Cl⁻ on one triangular face
    2. mer (meridional): Three Cl⁻ along a meridian (one pair trans, one cis)

Board Exam Question Types

  1. Write the IUPAC name of given complexes (2-3 complexes for 2-3 marks). — Guaranteed every year
  2. Write the formula from the IUPAC name. (1-2 marks)
  3. What type of isomerism is exhibited by [Co(NH₃)₅Br]SO₄ and [Co(NH₃)₅SO₄]Br? (1-2 marks) — Very common
  4. Draw the geometrical isomers of [Pt(NH₃)₂Cl₂]. (2 marks)
  5. Using CFT, explain why [CoF₆]³⁻ is paramagnetic while [Co(NH₃)₆]³⁺ is diamagnetic. (3 marks)
  6. What is the spectrochemical series? How does it help predict magnetic behaviour? (2-3 marks)
  7. Explain why d⁰ and d¹⁰ complexes are colourless. (1-2 marks)

Common Mistakes Students Make

  1. Wrong alphabetical order in naming. Students write "amminechloro..." instead of "chloridoammine..." Ligands must be listed in strict alphabetical order regardless of charge or number: ammine before chlorido, aqua before ammine, etc. (Note: prefixes like di-, tri- are ignored when alphabetising.)

  2. Forgetting to use -ate suffix for anionic complexes. When the complex is the anion (e.g., K₃[Fe(CN)₆]), the metal name changes: iron → ferrate, copper → cuprate, silver → argentate. Students write "potassium hexacyanidoiron(III)" instead of "potassium hexacyanidoferrate(III)."

  3. Confusing the CFT splitting diagram. In octahedral complexes, eᵍ (dz², dx²-y²) is the higher-energy set. In tetrahedral complexes, the splitting is inverted — t₂ is higher and e is lower. Drawing the wrong diagram in a 3-mark question costs you all 3 marks.

  4. Not distinguishing between linkage and ionisation isomerism. Linkage isomerism involves ambidentate ligands bonding through different atoms (NO₂⁻ through N vs O). Ionisation isomerism involves swapping an ion between the coordination sphere and the counter ion. Students often describe one but label it as the other.

  5. Miscalculating the oxidation state of the metal. The oxidation state must balance the overall charge. For [CoCl₂(en)₂]Cl: total charge on complex = +1, Cl⁻ contributes -2, en is neutral, so Co = +3. Many students forget that en is neutral or that water (aqua) is neutral.

4-Week Practice Plan

Week 1: Werner's Theory & IUPAC Naming

  • Read NCERT Section 5.1-5.6
  • Learn all ligand names and their donor atoms (make a flashcard set)
  • Practise naming 15 complexes from the NCERT exercises
  • Practise writing formulas from 10 IUPAC names
  • Master the 5-step naming algorithm until it is automatic

Week 2: Isomerism

  • Read NCERT Section 5.7
  • Draw all structural isomerism types with 2 examples each
  • Practise drawing cis-trans isomers for square planar and octahedral complexes
  • Understand optical isomerism with [Co(en)₃]³⁺ — draw the mirror images
  • Solve 10 "identify the type of isomerism" questions from previous years

Week 3: VBT and CFT

  • Read NCERT Sections 5.8-5.10
  • Memorise the spectrochemical series (use the mnemonic)
  • Draw the CFT splitting diagram for octahedral and tetrahedral fields
  • Practise filling d-electrons for d¹ through d¹⁰ in both strong and weak field
  • Solve 5 problems predicting magnetic nature (paramagnetic vs diamagnetic)

Week 4: Revision & Board-Pattern Practice

  • Solve 4 previous year board papers (coordination compound questions only)
  • Take a 30-minute timed chapter test
  • Revise naming rules, isomerism types, and CFT diagrams
  • Focus on the 3-mark CFT questions — they carry the most marks
  • Review the quick revision card below

Quick Revision Card

TopicKey Fact
Naming orderLigands (alphabetical) → Metal → (Oxidation state)
Anionic ligand suffix-ide → -ido, -ate → -ato, -ite → -ito
Special namesNH₃ = ammine, H₂O = aqua, CO = carbonyl
Anionic complex suffix-ate (ferrate, cuprate, argentate, aurate)
Linkage isomerismAmbidentate ligand, different donor atom (NO₂⁻, SCN⁻)
Ionisation isomerismIon swaps between coordination sphere and counter ion
Geometric isomerismcis-trans in square planar [MA₂B₂] and octahedral
Optical isomerismNon-superimposable mirror images, [Co(en)₃]³⁺
Octahedral CFTt₂ᵍ (lower) ← Δₒ → eᵍ (higher)
Tetrahedral CFTe (lower) ← Δₜ → t₂ (higher), Δₜ ≈ 4/9 Δₒ
Strong field ligandsCN⁻, CO, NH₃, en → low spin, small unpaired e⁻
Weak field ligandsI⁻, Br⁻, Cl⁻, F⁻ → high spin, more unpaired e⁻
Colourless complexesd⁰ and d¹⁰ (no d-d transition possible)

One-liner mnemonics:

  • "LAM-O" for naming — Ligands Alphabetically, Metal, Oxidation state
  • "AMP" for ambidentate — Ambidentate has Multiple Possible donor atoms
  • Spectrochemical series: "I Brought Stamps, Chlorine Says Funny..." (weak → strong)
  • "t₂ᵍ is lower in octahedral, t₂ is higher in tetrahedral" — the g subscript tells you it is the lower one

Frequently Asked Questions

How many marks does Coordination Compounds carry?

6 marks out of 70 in the CBSE Class 12 Chemistry theory paper. It is a moderate-weightage chapter but highly scoring because the question types are predictable — naming, isomerism, and CFT.

Is CFT more important than VBT for the board exam?

Yes. CFT questions appear more frequently and carry more marks (2-3 marks). VBT is usually limited to 1-mark MCQs asking about hybridisation of a specific complex. Focus 70% of your time on CFT and 30% on VBT.

How do I memorise the spectrochemical series?

Use a mnemonic sentence where each word starts with the ligand's first letter. The most common one is: "I Brought Stamps, Chlorine Says Funny, Oh Her Oxalate Has Not Nailed All Carbon Notes Completely Over." Practise writing it 5 times from memory and it sticks.

What is the difference between high spin and low spin?

In a strong ligand field (large Δ), electrons prefer to pair up in the lower-energy orbitals → fewer unpaired electrons → low spin. In a weak ligand field (small Δ), electrons prefer to stay unpaired across all orbitals (Hund's rule dominates) → more unpaired electrons → high spin. The same metal with different ligands can form both types.

Is cisplatin important for boards?

Yes. cis-[Pt(NH₃)₂Cl₂] (cisplatin) is used as an anti-cancer drug. The board can ask you to draw its structure, name it, or distinguish it from the trans isomer. It is a common 1-2 mark question.

How do I find the oxidation state of the metal in a complex?

Set up the charge equation: metal charge + sum of ligand charges = overall charge of the complex ion. Neutral ligands (NH₃, H₂O, en, CO) contribute 0. Anionic ligands contribute their charge (Cl⁻ = -1, ox²⁻ = -2). Solve for the metal's charge.

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