संक्षेप में: CBSE Class 12 Maths का paper 80 marks का होता है। Calculus से 44% (35 marks), Algebra से 10% (8 marks), Vectors & 3D से 17% (14 marks), Linear Programming से 6% (5 marks), और Probability से 13% (10 marks) questions आते हैं। इस guide में सभी 13 chapters के most important questions with solutions दिए हैं।
CBSE Class 12 Maths Paper Pattern 2027
| Section | Marks | Questions |
|---|---|---|
| Section A (MCQ) | 20 | 20 questions (1 mark each) |
| Section B (VSA) | 10 | 5 questions (2 marks each) |
| Section C (SA) | 18 | 6 questions (3 marks each) |
| Section D (LA) | 20 | 4 questions (5 marks each) |
| Section E (Case Study) | 12 | 3 questions (4 marks each) |
| Total | 80 | 38 questions |
Unit-wise Marks Distribution
| Unit | Chapters | Marks |
|---|---|---|
| Relations and Functions | Ch 1, 2 | 8 |
| Algebra (Matrices, Determinants) | Ch 3, 4 | 10 |
| Calculus | Ch 5, 6, 7, 8 | 35 |
| Vectors and 3D Geometry | Ch 10, 11 | 14 |
| Linear Programming | Ch 12 | 5 |
| Probability | Ch 13 | 8 |
Chapter 1: Relations and Functions
इस chapter से 3-5 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
Let A = {1, 2, 3}. The number of equivalence relations on A containing (1, 2) is:
- (a) 1
- (b) 2 ✓
- (c) 3
- (d) 4
-
If f: R → R is defined by f(x) = 3x + 2, then f⁻¹(x) is:
- (a) (x - 2)/3 ✓
- (b) (x + 2)/3
- (c) 3x - 2
- (d) 3x + 2
-
The function f: N → N defined by f(n) = n + 1 is:
- (a) One-one and onto
- (b) One-one but not onto ✓
- (c) Onto but not one-one
- (d) Neither one-one nor onto
-
If f(x) = x² and g(x) = √x, then (gof)(x) is:
- (a) x²
- (b) √x
- (c) |x| ✓
- (d) x
-
A relation R on set A is symmetric if:
- (a) (a, b) ∈ R ⟹ (b, a) ∈ R ✓
- (b) (a, a) ∈ R for all a
- (c) (a, b), (b, c) ∈ R ⟹ (a, c) ∈ R
- (d) None of these
Important Questions (2-5 marks)
Q1. (3 marks) Check whether the relation R in the set {1, 2, 3} given by R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)} is reflexive, symmetric, or transitive.
Solution:
- Reflexive: (1,1), (2,2), (3,3) ∈ R ✓ Yes
- Symmetric: (1,2) ∈ R but (2,1) ∉ R ✗ No
- Transitive: (1,2), (2,3) ∈ R but (1,3) ∉ R ✗ No
Q2. (3 marks) Show that the function f: R → R defined by f(x) = 2x + 3 is one-one and onto.
Solution:
- One-one: Let f(x₁) = f(x₂)
- 2x₁ + 3 = 2x₂ + 3
- x₁ = x₂ ✓
- Onto: For any y ∈ R, x = (y-3)/2 ∈ R
- f(x) = 2((y-3)/2) + 3 = y ✓
Q3. (5 marks) Let A = R - {3} and B = R - {1}. Consider the function f: A → B defined by f(x) = (x - 2)/(x - 3). Show that f is one-one and onto. ⭐
Chapter 2: Inverse Trigonometric Functions
इस chapter से 3-5 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
The principal value of sin⁻¹(1/2) is:
- (a) π/6 ✓
- (b) π/3
- (c) 5π/6
- (d) -π/6
-
tan⁻¹(1) + tan⁻¹(2) + tan⁻¹(3) equals:
- (a) 0
- (b) π ✓
- (c) π/2
- (d) 2π
-
The value of cos⁻¹(cos(7π/6)) is:
- (a) 7π/6
- (b) 5π/6 ✓
- (c) π/6
- (d) π/3
-
sin⁻¹x + cos⁻¹x equals:
- (a) 0
- (b) π/2 ✓
- (c) π
- (d) 2π
-
The domain of sin⁻¹(2x) is:
- (a) [-1, 1]
- (b) [-1/2, 1/2] ✓
- (c) [0, 1]
- (d) R
Important Questions (2-5 marks)
Q1. (2 marks) Find the value of tan⁻¹(1) + cos⁻¹(-1/2) + sin⁻¹(-1/2).
Solution:
- tan⁻¹(1) = π/4
- cos⁻¹(-1/2) = 2π/3
- sin⁻¹(-1/2) = -π/6
- Sum = π/4 + 2π/3 - π/6 = 3π/12 + 8π/12 - 2π/12 = 9π/12 = 3π/4
Q2. (3 marks) Prove that: tan⁻¹(1/2) + tan⁻¹(1/3) = π/4 ⭐
Solution: Using tan⁻¹x + tan⁻¹y = tan⁻¹((x+y)/(1-xy))
tan⁻¹(1/2) + tan⁻¹(1/3) = tan⁻¹((1/2 + 1/3)/(1 - 1/6)) = tan⁻¹((5/6)/(5/6)) = tan⁻¹(1) = π/4
Q3. (3 marks) Simplify: tan⁻¹(cosx/(1 + sinx))
Chapter 3: Matrices
इस chapter से 4-6 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
If A is a square matrix such that A² = A, then (I + A)³ - 7A equals:
- (a) A
- (b) I - A
- (c) I ✓
- (d) 3A
-
If A = [aᵢⱼ] is a 3×3 matrix and Aᵢⱼ is the cofactor of aᵢⱼ, then a₁₁A₁₁ + a₁₂A₁₂ + a₁₃A₁₃ equals:
- (a) 0
- (b) 1
- (c) |A| ✓
- (d) -|A|
-
If A is a 3×3 matrix such that |A| = 5, then |adj A| equals:
- (a) 5
- (b) 25 ✓
- (c) 125
- (d) 1/5
-
The number of all possible matrices of order 2×2 with each entry 0 or 1 is:
- (a) 8
- (b) 16 ✓
- (c) 32
- (d) 64
-
If A = [1 2; 3 4], then A⁻¹ exists if:
- (a) |A| = 0
- (b) |A| ≠ 0 ✓
- (c) A is singular
- (d) A is not square
Important Questions (2-5 marks)
Q1. (3 marks) If A = [2 3; 1 2], find A⁻¹ and verify that AA⁻¹ = I.
Solution:
- |A| = 4 - 3 = 1 ≠ 0, so A⁻¹ exists
- adj A = [2 -3; -1 2]
- A⁻¹ = (1/|A|) × adj A = [2 -3; -1 2]
Verification: AA⁻¹ = [2 3; 1 2][2 -3; -1 2] = [1 0; 0 1] = I ✓
Q2. (5 marks) Using matrices, solve the system of equations: ⭐
- x + 2y + z = 7
- x + 3z = 11
- 2x - 3y = 1
Solution: Matrix form: AX = B where A = [1 2 1; 1 0 3; 2 -3 0], X = [x; y; z], B = [7; 11; 1]
Find |A|, adj A, then X = A⁻¹B
Chapter 4: Determinants
इस chapter से 4-6 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
If |A| = 2, then |3A| for a 3×3 matrix equals:
- (a) 6
- (b) 18
- (c) 54 ✓
- (d) 8
-
The value of |1 a a²; 1 b b²; 1 c c²| is:
- (a) (a-b)(b-c)(c-a) ✓
- (b) abc
- (c) 0
- (d) 1
-
If A is a 3×3 matrix and |A| = 8, then |A'| equals:
- (a) 8 ✓
- (b) -8
- (c) 1/8
- (d) 64
-
Area of triangle with vertices (0,0), (4,0), (0,3) using determinants is:
- (a) 12
- (b) 6 ✓
- (c) 24
- (d) 3
-
If |2x 5; 8 x| = |6 5; 8 3|, then x equals:
- (a) 3
- (b) ±3 ✓
- (c) 6
- (d) ±6
Important Questions (2-5 marks)
Q1. (3 marks) Using properties of determinants, prove that: |a-b-c 2a 2a; 2b b-c-a 2b; 2c 2c c-a-b| = (a+b+c)³ ⭐
Q2. (3 marks) Find the area of the triangle with vertices (1, 0), (6, 0), (4, 3) using determinants.
Solution: Area = (1/2)|x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)| = (1/2)|1(0-3) + 6(3-0) + 4(0-0)| = (1/2)|-3 + 18 + 0| = (1/2)(15) = 7.5 sq units
Q3. (5 marks) Solve using Cramer's rule: ⭐
- 2x + 3y + z = 9
- x + 2y + 3z = 6
- 3x + y + 2z = 8
Chapter 5: Continuity and Differentiability
इस chapter से 6-8 marks के questions आते हैं। यह Calculus का important chapter है।
MCQ Questions (1 mark each)
-
The function f(x) = |x| is:
- (a) Continuous everywhere ✓
- (b) Differentiable everywhere
- (c) Not continuous at x = 0
- (d) None of these
-
If y = sin⁻¹x, then dy/dx equals:
- (a) 1/√(1-x²) ✓
- (b) -1/√(1-x²)
- (c) 1/√(1+x²)
- (d) -1/√(1+x²)
-
d/dx(eˣ) equals:
- (a) eˣ ✓
- (b) xeˣ⁻¹
- (c) eˣ/x
- (d) eˣ⁺¹
-
If y = log(sinx), then dy/dx equals:
- (a) cotx ✓
- (b) tanx
- (c) secx
- (d) cosecx
-
The derivative of xˣ is:
- (a) xˣ(1 + logx) ✓
- (b) xˣ⁻¹
- (c) xˣlogx
- (d) xxˣ⁻¹
Important Questions (2-5 marks)
Q1. (2 marks) Find the value of k if the function f(x) = {kx + 1, if x ≤ 5; 3x - 5, if x > 5} is continuous at x = 5.
Solution: For continuity at x = 5:
- LHL = k(5) + 1 = 5k + 1
- RHL = 3(5) - 5 = 10
- f(5) = 5k + 1
5k + 1 = 10 k = 9/5
Q2. (3 marks) If y = (sinx)ˣ, find dy/dx. ⭐
Solution: Taking log: log y = x log(sinx)
Differentiating: (1/y)(dy/dx) = log(sinx) + x(cosx/sinx) dy/dx = y[log(sinx) + x cotx] dy/dx = (sinx)ˣ[log(sinx) + x cotx]
Q3. (5 marks) If y = (cos⁻¹x)², prove that (1-x²)y₂ - xy₁ - 2 = 0 ⭐
Q4. (3 marks) Differentiate: tan⁻¹((√(1+x²) - 1)/x) with respect to x.
Chapter 6: Application of Derivatives
इस chapter से 6-8 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
The rate of change of area of a circle with respect to its radius r when r = 3 cm is:
- (a) 6π cm²/cm ✓
- (b) 3π cm²/cm
- (c) 9π cm²/cm
- (d) 12π cm²/cm
-
The function f(x) = x³ - 3x is:
- (a) Increasing in (-1, 1)
- (b) Decreasing in (-1, 1) ✓
- (c) Increasing everywhere
- (d) Decreasing everywhere
-
The maximum value of sinx + cosx is:
- (a) 1
- (b) √2 ✓
- (c) 2
- (d) 1/√2
-
The slope of tangent to y = x² at x = 2 is:
- (a) 2
- (b) 4 ✓
- (c) 8
- (d) 1
-
If f(x) = x² - 4x + 5, then the minimum value of f(x) is:
- (a) 0
- (b) 1 ✓
- (c) 4
- (d) 5
Important Questions (2-5 marks)
Q1. (3 marks) Find the intervals in which f(x) = 2x³ - 9x² + 12x - 5 is increasing or decreasing.
Solution: f'(x) = 6x² - 18x + 12 = 6(x² - 3x + 2) = 6(x-1)(x-2)
Critical points: x = 1, 2
| Interval | Sign of f'(x) | Nature |
|---|---|---|
| (-∞, 1) | + | Increasing |
| (1, 2) | - | Decreasing |
| (2, ∞) | + | Increasing |
Q2. (5 marks) Find the equation of tangent and normal to the curve y = x³ at the point (1, 1). ⭐
Solution:
- dy/dx = 3x²
- At (1, 1): slope = 3(1)² = 3
Tangent: y - 1 = 3(x - 1) → 3x - y - 2 = 0
Normal: y - 1 = (-1/3)(x - 1) → x + 3y - 4 = 0
Q3. (5 marks) A rectangular sheet of tin 45 cm × 24 cm is to be made into a box without top by cutting off squares from corners and folding up the flaps. What should be the side of the square to be cut off so that the volume of the box is maximum? ⭐
Practice CBSE Maths on Padhaao
AI tutor with 10 learning modes · Quiz, Flashcards, Exam Practice & more · 3 free chapters daily
Chapter 7: Integrals
इस chapter से 8-10 marks के questions आते हैं। यह सबसे important chapter है।
MCQ Questions (1 mark each)
-
∫eˣ(sinx + cosx)dx equals:
- (a) eˣsinx + C ✓
- (b) eˣcosx + C
- (c) eˣ(sinx - cosx) + C
- (d) eˣ + C
-
∫dx/(x² + a²) equals:
- (a) (1/a)tan⁻¹(x/a) + C ✓
- (b) tan⁻¹(x/a) + C
- (c) (1/a)sin⁻¹(x/a) + C
- (d) log|x + √(x²+a²)| + C
-
∫₀^π sinx dx equals:
- (a) 0
- (b) 1
- (c) 2 ✓
- (d) -2
-
∫x²eˣdx equals:
- (a) eˣ(x² - 2x + 2) + C ✓
- (b) eˣ(x² + 2x + 2) + C
- (c) x²eˣ + C
- (d) eˣx² - 2xeˣ + C
-
∫₀^(π/2) log(tanx)dx equals:
- (a) 0 ✓
- (b) 1
- (c) π/2
- (d) π/4
Important Questions (2-5 marks)
Q1. (3 marks) Evaluate: ∫dx/(x² - 6x + 13)
Solution: x² - 6x + 13 = (x-3)² + 4
∫dx/((x-3)² + 2²) = (1/2)tan⁻¹((x-3)/2) + C
Q2. (3 marks) Evaluate: ∫(x + 1)/(x² + x + 1)dx ⭐
Solution: Let x + 1 = A(2x + 1) + B Comparing: A = 1/2, B = 1/2
∫(x+1)/(x²+x+1)dx = (1/2)∫(2x+1)/(x²+x+1)dx + (1/2)∫dx/(x²+x+1)
= (1/2)log|x²+x+1| + (1/2) × (2/√3)tan⁻¹((2x+1)/√3) + C
Q3. (5 marks) Evaluate: ∫₀^(π/2) (sinx - cosx)/(1 + sinx cosx)dx ⭐
Q4. (5 marks) Evaluate using integration by parts: ∫x²sin⁻¹x dx ⭐
Chapter 8: Application of Integrals
इस chapter से 5-6 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
Area bounded by y = x², x-axis and x = 2 is:
- (a) 4/3
- (b) 8/3 ✓
- (c) 2/3
- (d) 16/3
-
Area of region bounded by y = |x| and y = 2 is:
- (a) 2
- (b) 4 ✓
- (c) 8
- (d) 1
-
Area enclosed by y = sinx, x-axis from 0 to π is:
- (a) 1
- (b) 2 ✓
- (c) π
- (d) 0
Important Questions (5 marks)
Q1. (5 marks) Find the area of the region bounded by the curve y² = 4x and the line x = 3. ⭐
Solution: y² = 4x → y = ±2√x
Area = 2∫₀³ 2√x dx = 4[x^(3/2)/(3/2)]₀³ = 4 × (2/3) × 3^(3/2) = (8/3) × 3√3 = 8√3 sq units
Q2. (5 marks) Find the area of the region bounded by the ellipse x²/16 + y²/9 = 1. ⭐
Solution: Area = 4 × ∫₀⁴ (3/4)√(16-x²) dx = 3∫₀⁴ √(16-x²) dx = 3 × (1/2)[x√(16-x²) + 16sin⁻¹(x/4)]₀⁴ = 3 × (1/2) × 16 × (π/2) = 12π sq units
Q3. (5 marks) Find the area of the region bounded by y = x² and y = x.
Chapter 9: Differential Equations
इस chapter से 5-6 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
The order of the differential equation (d²y/dx²)³ + (dy/dx)² + y = 0 is:
- (a) 1
- (b) 2 ✓
- (c) 3
- (d) 6
-
The degree of dy/dx + sin(dy/dx) = 0 is:
- (a) 1
- (b) 2
- (c) Not defined ✓
- (d) 0
-
The integrating factor of dy/dx + y/x = x² is:
- (a) x ✓
- (b) 1/x
- (c) eˣ
- (d) logx
-
Solution of dy/dx = y/x is:
- (a) y = cx ✓
- (b) y = c/x
- (c) xy = c
- (d) y = x + c
-
The general solution of dy/dx = eˣ⁺ʸ is:
- (a) eˣ + e⁻ʸ = c ✓
- (b) eˣ + eʸ = c
- (c) e⁻ˣ + eʸ = c
- (d) eˣ - eʸ = c
Important Questions (2-5 marks)
Q1. (3 marks) Solve: dy/dx + 2y tanx = sinx
Solution: This is linear DE: dy/dx + Py = Q P = 2tanx, Q = sinx
IF = e^∫2tanx dx = e^(2log|secx|) = sec²x
Solution: y × sec²x = ∫sinx × sec²x dx y sec²x = ∫secx tanx dx = secx + C y = cosx + C cos²x
Q2. (5 marks) Solve: (x² - y²)dx + 2xy dy = 0 ⭐
Q3. (5 marks) Solve: x dy/dx + y = x logx ⭐
Chapter 10: Vector Algebra
इस chapter से 5-6 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
If |a⃗| = 3, |b⃗| = 4 and a⃗·b⃗ = 6, then |a⃗ × b⃗| equals:
- (a) 6
- (b) 6√3 ✓
- (c) 12
- (d) 6√2
-
If a⃗ × b⃗ = c⃗ × d⃗ and a⃗ × c⃗ = b⃗ × d⃗, then:
- (a) a⃗ - d⃗ is parallel to b⃗ - c⃗ ✓
- (b) a⃗ + d⃗ is parallel to b⃗ + c⃗
- (c) a⃗ - b⃗ is parallel to c⃗ - d⃗
- (d) None of these
-
The projection of a⃗ = 2î - ĵ + k̂ on b⃗ = î - 2ĵ + k̂ is:
- (a) 5/√6 ✓
- (b) √6/5
- (c) 5/6
- (d) 6/5
-
If a⃗ and b⃗ are perpendicular, then a⃗·b⃗ equals:
- (a) 1
- (b) -1
- (c) 0 ✓
- (d) |a⃗||b⃗|
-
The area of parallelogram with adjacent sides a⃗ and b⃗ is:
- (a) a⃗·b⃗
- (b) |a⃗ × b⃗| ✓
- (c) a⃗ × b⃗
- (d) |a⃗·b⃗|
Important Questions (2-5 marks)
Q1. (3 marks) Find the area of the triangle with vertices A(1, 1, 2), B(2, 3, 5), C(1, 5, 5).
Solution: AB⃗ = î + 2ĵ + 3k̂ AC⃗ = 0î + 4ĵ + 3k̂
AB⃗ × AC⃗ = |î ĵ k̂; 1 2 3; 0 4 3| = î(6-12) - ĵ(3-0) + k̂(4-0) = -6î - 3ĵ + 4k̂
|AB⃗ × AC⃗| = √(36 + 9 + 16) = √61
Area = (1/2)|AB⃗ × AC⃗| = √61/2 sq units
Q2. (3 marks) Find the unit vector perpendicular to both a⃗ = 2î + ĵ + k̂ and b⃗ = î - ĵ + 2k̂. ⭐
Q3. (5 marks) Prove that [a⃗ + b⃗, b⃗ + c⃗, c⃗ + a⃗] = 2[a⃗, b⃗, c⃗] ⭐
Chapter 11: Three Dimensional Geometry
इस chapter से 6-8 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
The direction cosines of a line equally inclined to the axes are:
- (a) (1, 1, 1)
- (b) (1/√3, 1/√3, 1/√3) ✓
- (c) (1/3, 1/3, 1/3)
- (d) (√3, √3, √3)
-
The angle between the lines (x-1)/2 = (y-2)/3 = (z-3)/4 and (x-4)/5 = (y-1)/2 = z/1 is:
- (a) cos⁻¹(20/√(29×30))
- (b) cos⁻¹(20/(√29 × √30)) ✓
- (c) 90°
- (d) 0°
-
The distance of point (1, 2, 3) from the plane x + y + z = 11 is:
- (a) 5/√3 ✓
- (b) √3/5
- (c) 5√3
- (d) 3/√5
-
The equation of plane passing through (1, 2, 3) and parallel to xy-plane is:
- (a) x = 1
- (b) y = 2
- (c) z = 3 ✓
- (d) x + y + z = 6
-
The shortest distance between the lines r⃗ = î + ĵ + λ(2î - ĵ + k̂) and r⃗ = 2î + ĵ - k̂ + μ(3î - 5ĵ + 2k̂) is:
- (a) 10/√59 ✓
- (b) √59/10
- (c) 59/10
- (d) 10/59
Important Questions (2-5 marks)
Q1. (3 marks) Find the equation of the plane passing through (1, 1, 1), (1, -1, 1) and (-7, -3, -5).
Q2. (5 marks) Find the shortest distance between the lines: ⭐
- r⃗ = (1-t)î + (t-2)ĵ + (3-2t)k̂
- r⃗ = (s+1)î + (2s-1)ĵ - (2s+1)k̂
Q3. (5 marks) Find the equation of the plane passing through the intersection of planes x + y + z = 1 and 2x + 3y + 4z = 5 and perpendicular to the plane x - y + z = 0. ⭐
Chapter 12: Linear Programming
इस chapter से 5 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
The corner points of the feasible region determined by x + y ≤ 4, x ≥ 0, y ≥ 0 are:
- (a) (0, 0), (4, 0), (0, 4) ✓
- (b) (0, 0), (4, 4)
- (c) (4, 0), (0, 4)
- (d) (0, 0), (4, 0), (4, 4), (0, 4)
-
The maximum value of Z = 3x + 4y subject to x + y ≤ 4, x ≥ 0, y ≥ 0 is:
- (a) 12
- (b) 16 ✓
- (c) 7
- (d) 0
-
In a LPP, if the objective function Z = ax + by has the same maximum value on two corner points, then:
- (a) The maximum occurs at every point on the line joining them ✓
- (b) The maximum occurs only at one point
- (c) There is no maximum
- (d) None of these
Important Questions (5 marks)
Q1. (5 marks) Maximize Z = 5x + 3y subject to: ⭐
- 3x + 5y ≤ 15
- 5x + 2y ≤ 10
- x ≥ 0, y ≥ 0
Solution: Corner points: (0, 0), (2, 0), (0, 3), (20/19, 45/19)
| Point | Z = 5x + 3y |
|---|---|
| (0, 0) | 0 |
| (2, 0) | 10 |
| (0, 3) | 9 |
| (20/19, 45/19) | 100/19 + 135/19 = 235/19 ≈ 12.37 |
Maximum Z = 235/19 at (20/19, 45/19)
Q2. (5 marks) A manufacturer produces two types of steel trunks. He has two machines A and B. For completing the first type, it requires 3 hours on machine A and 3 hours on machine B. For the second type, it requires 3 hours on machine A and 2 hours on machine B. Machine A can work for 18 hours and B for 15 hours per day. He earns a profit of ₹30 and ₹25 per trunk of first and second type respectively. How many trunks of each type should he make to maximize profit? ⭐
Chapter 13: Probability
इस chapter से 8-10 marks के questions आते हैं।
MCQ Questions (1 mark each)
-
If P(A) = 0.4, P(B) = 0.3 and P(A∩B) = 0.2, then P(A|B) equals:
- (a) 2/3 ✓
- (b) 1/2
- (c) 1/3
- (d) 1/4
-
If A and B are independent events with P(A) = 0.3 and P(B) = 0.4, then P(A∩B) equals:
- (a) 0.12 ✓
- (b) 0.7
- (c) 0.1
- (d) 0.5
-
The mean of a binomial distribution is 5 and variance is 4. Then n equals:
- (a) 20
- (b) 25 ✓
- (c) 10
- (d) 15
-
If X follows binomial distribution with n = 5 and p = 1/2, then P(X = 3) equals:
- (a) 5/16
- (b) 10/32 ✓
- (c) 1/32
- (d) 5/32
-
For two events A and B, P(A∪B) = P(A) + P(B) if:
- (a) A and B are independent
- (b) A and B are mutually exclusive ✓
- (c) P(A|B) = P(A)
- (d) P(B|A) = P(B)
Important Questions (2-5 marks)
Q1. (3 marks) A bag contains 4 red and 4 black balls. Another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag. Find the probability that the ball drawn is red.
Solution: P(Bag 1) = 1/2, P(Bag 2) = 1/2 P(Red|Bag 1) = 4/8 = 1/2 P(Red|Bag 2) = 2/8 = 1/4
P(Red) = P(Bag 1) × P(Red|Bag 1) + P(Bag 2) × P(Red|Bag 2) = (1/2)(1/2) + (1/2)(1/4) = 1/4 + 1/8 = 3/8
Q2. (5 marks) There are three coins. One is a two-headed coin, another is a biased coin that comes up heads 75% of the time and the third is an unbiased coin. One of the three coins is chosen at random and tossed. If it shows heads, what is the probability that it was the two-headed coin? ⭐
Solution: Let A₁ = two-headed, A₂ = biased, A₃ = unbiased P(A₁) = P(A₂) = P(A₃) = 1/3
P(H|A₁) = 1, P(H|A₂) = 3/4, P(H|A₃) = 1/2
P(H) = (1/3)(1) + (1/3)(3/4) + (1/3)(1/2) = 1/3 + 1/4 + 1/6 = 9/12 = 3/4
By Bayes' theorem: P(A₁|H) = P(A₁) × P(H|A₁) / P(H) = (1/3 × 1) / (3/4) = (1/3) × (4/3) = 4/9
Q3. (5 marks) A random variable X has the following probability distribution: ⭐
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(X) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k²+k |
Find: (i) k (ii) P(X < 3) (iii) P(X > 6) (iv) Mean of X
Q4. (5 marks) Five cards are drawn successively with replacement from a well-shuffled deck of 52 cards. What is the probability that: (i) all the five cards are spades? (ii) only 3 cards are spades? (iii) none is a spade?
Most Important Topics — CBSE 2027
| Chapter | Most Important Topics | Expected Marks |
|---|---|---|
| Ch 1 | Equivalence relations, One-one onto functions | 3-4 |
| Ch 2 | Inverse trigonometric identities | 2-3 |
| Ch 3-4 | Matrix inverse, Cramer's rule, Determinant properties | 6-8 |
| Ch 5 | Logarithmic differentiation, Implicit differentiation | 4-5 |
| Ch 6 | Maxima/Minima word problems, Rate of change | 5-6 |
| Ch 7 | Integration by parts, Partial fractions, Definite integrals | 8-10 |
| Ch 8 | Area under curves | 5-6 |
| Ch 9 | Linear DE, Homogeneous DE | 4-5 |
| Ch 10 | Scalar triple product, Vector product | 4-5 |
| Ch 11 | Shortest distance, Plane equations | 6-8 |
| Ch 12 | LPP graphical method | 5 |
| Ch 13 | Bayes' theorem, Binomial distribution | 8-10 |
Case Study Questions — Sample
Case Study 1 (4 marks): A company manufactures two types of novelty souvenirs made of plywood. Souvenirs of type A require 5 minutes each for cutting and 10 minutes each for assembling. Souvenirs of type B require 8 minutes each for cutting and 8 minutes each for assembling. There are 3 hours 20 minutes available for cutting and 4 hours for assembling. The profit is ₹50 each for type A and ₹60 each for type B.
(i) Formulate the LPP. (ii) Find the maximum profit. (iii) How many souvenirs of each type should be made?
Case Study 2 (4 marks): In a class of 60 students, 30 opted for NCC, 32 opted for NSS and 24 opted for both NCC and NSS. If one of these students is selected at random:
(i) Find P(student opted for NCC or NSS) (ii) Find P(student opted for NCC but not NSS) (iii) Find P(student opted for NSS given that student opted for NCC)
Frequently Asked Questions
CBSE Class 12 Maths में 80 में से 70+ marks कैसे लाएं?
- Calculus (35 marks) — Integration और Differentiation पर focus करो
- 3D Geometry (14 marks) — Formulas याद करो, numericals practice करो
- Probability (8 marks) — Bayes' theorem और Binomial distribution master करो
- Case Studies (12 marks) — Previous year case studies solve करो
कौन से chapters सबसे ज्यादा marks carry करते हैं?
- Integrals (Ch 7) — 8-10 marks
- Three Dimensional Geometry (Ch 11) — 6-8 marks
- Probability (Ch 13) — 8-10 marks
- Application of Derivatives (Ch 6) — 5-6 marks
Integration की तैयारी कैसे करें?
- सभी standard formulas याद करो
- Integration by parts के लिए ILATE rule याद करो
- Partial fractions के सभी cases practice करो
- Daily 10-15 integration problems solve करो
Padhaao पर Practice करें
CBSE Class 12 Maths के सभी chapters Padhaao पर available हैं।
| Feature | Benefit |
|---|---|
| 10 Learning Modes | Quiz, Notes, Flashcards, Exam Practice |
| Chapter-wise Practice | हर chapter अलग से |
| Important Questions | Board exam pattern पर based |
| Free Daily | रोज़ 3 chapters मुफ्त |
Padhaao Pricing:
- Free: 3 chapters/day
- Pro: ₹21/month (annual) — unlimited access
CBSE Class 12 Maths Practice शुरू करें — Free →
Related Guides
₹21/mo (annual plan)
Padhaao covers every CBSE Maths chapter
1,005 chapters across all subjects. 2.5 crore+ students. Pro from ₹21/month (annual plan).
Practice CBSE Maths chapters with AI
Every chapter from your syllabus. 10 learning modes. 3 free every day.
Start Maths