Class 12 Maths - ISC
Relations and Functions
The chapter 'Relations and Functions' in Class 12 ISC Mathematics builds upon foundational set theory by advancing into specialized mappings between sets. Students explore types of relations including reflexive, symmetric, transitive, and equivalence relations, which are crucial for structuring logical arguments. The latter half delves into functions, focusing strictly on injectivity (one-one), surjectivity (onto), and bijectivity, alongside the concept of invertible functions and binary operations. For the ISC board exams, this chapter serves as a high-scoring foundational topic that frequently appears in both short-answer and long-answer sections, testing analytical thinking and rigorous mathematical proof-writing.
Start Learning FreeKey Concepts
Reflexive Relation
A relation R on set A is reflexive if every element relates to itself, meaning (a, a) belongs to R for all a in A.
Symmetric Relation
A relation R is symmetric if whenever (a, b) belongs to R, then (b, a) must also belong to R for all a, b in A.
Transitive Relation
A relation R is transitive if whenever (a, b) and (b, c) belong to R, then (a, c) must also belong to R.
Equivalence Relation
A relation is called an equivalence relation if it is simultaneously reflexive, symmetric, and transitive.
One-One (Injective) Function
A function f: A -> B is one-one if distinct elements in domain A have distinct images in codomain B, meaning f(a1) = f(a2) implies a1 = a2.
Onto (Surjective) Function
A function f: A -> B is onto if every element in the codomain B has at least one pre-image in the domain A.
Important Formulas
Board Exam Info
In the ISC Class 12 Mathematics examination, this chapter typically carries around 6 to 8 marks. Questions usually include proving whether a given relation is an equivalence relation, testing functions for injectivity and surjectivity, and finding the inverse of a given bijective function.
Frequently Asked Questions
How do I prove a function is one-one for all real numbers?
Assume f(x1) = f(x2) and solve the equation algebraically. If you can definitively prove that x1 must equal x2 with no alternative solutions, the function is one-one.
What is the easiest way to disprove a relation is transitive?
Provide a specific counterexample. Find elements a, b, and c where (a, b) and (b, c) are in the relation, but (a, c) is missing.
Do I need to find the range to prove a function is onto?
Yes, proving a function is onto requires showing that the range of the function is identically equal to its given codomain.
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